Every final score posted during the 1946 Major League Baseball season, tabulated by winning-team runs and losing-team runs.
Baseball games end with a final score, like 8–6. The number across the top is how many runs the winning team scored; the number down the side is how many runs the losing team scored. Where a column and row meet, that square shows how many 1946 games ended with that score — click it to see them.
The 1946 season produced 1,249 games between 16 clubs, running from April 16, 1946 to October 15, 1946. Those games ended in 107 different final scores, 28 of which occurred exactly once all season. The most common result was 3–2, posted 81 times — 6.5% of the season's games. The season also produced nine tie games, which sit on the board's diagonal.
Teams combined for 8.01 runs per game in 1946, 0.78 runs below the 1901-onward average of 8.79. Shutouts accounted for 209 games (16.7% of the total), and 407 of the 1,240 decided games were settled by a single run (32.8%).
The highest-scoring game of the season came on May 18, 1946, when the Boston Red Sox beat the St. Louis Browns 18–8 — 26 combined runs. The widest margin was 16 runs: the Chicago Cubs over the New York Giants 19–3 on May 18, 1946.
No final score appeared for the first time in major league history during 1946. Every score posted this season had already happened at least once in an earlier year.
This season sits in the years around the Second World War and the integration of the major leagues, played by sixteen clubs on a 154-game schedule.